Question

In a single toss of 2 fair (evenly-weighted) six-sided dice, find the probability that their sum will be at most 9.

Answer 1

10/36or 5/18.......the possibilities are
3,6 4,5 4,6 5,4 5,5 5,6 6,3 6,4 6,5 6,6

Answer 2

Answer:

Answer: 5/6

Explanation:

 

There are 6 possibilities on each die. On 2 dice, there are 6 * 6 = 36 possibilities

There are 6 cases where sum >= 10: (4,6), (5,5), (5,6), (6,4), (6,5), (6,6)

This gives us probability(sum >= 10) = 6/36 = 1/6

That means probability(sum <= 9) = 1 - 1/6 = 5/6