In a slab under steady state conduction if the thermal conductivity increases along the thickness, the temperature gradient along the direction will become
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In steady state conduction with thermal conductivity given by k=k ₂ (1+β) ... Will be the same as flow depends on the thickness only 13. ... The temperature will drop at a faster rate along the length b.
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In a slab under steady-state conduction, if the thermal conductivity increases along with the thickness, the temperature gradient along with the direction decreases.
- During steady-state conditions, the rate of heat flow remains constant i.e. dQ / dt = Constant
- The formula for heat conduction across a conductor = dQ / dt
= k A (d∅/ dl)
(Here, k = thermal conductivity, A = area of cross-section, ∅ = temperature, and l is the length)
- Since dQ / dt and A are constant in the given question, on cross multiplying we get k ∝ dl / d∅ or k is inversely proportional to the temperature gradient.
- So as K increases along with the thickness of the conductor, the temperature gradient decreases.
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