Math, asked by rshwerma150, 8 months ago

In a small town named Frankfort, the population today
is 6813. For the last eight years, the population
has grown by 87% every year. t the growth
stay the same, what is the expected population
in Frankfort 7 years from today?​

Answers

Answered by mudavathramcharan5
0

if we find one year then we able to find 7 years

100% - 6813

187% -x

do the cross multiplication

187×6813÷100=12,740.31

for 7 years =12,740×7=89,182.17

so now add thepreset population and 7 years population

6813+89182.17 =95,995.17

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