Question

In a soccer practice session, the football is kept at the centre of the field 40 yards from the 10 ft high goalposts. A goal is attempted by kicking the football at a speed of 64 ft/s at an angle of 45° to the horizontal. Will the ball reach the goalpost?Concept of Physics - 1, Chapter "Rest and Motion: Kinematics

Answer 1

Known data:

x=40yd=120ft

h=10ft

vo=64ft/s

θ=45°

Unknowns:

y=?

We will determine the vertical position of the ball when it reaches the goal, from the equation of the parabolic trajectory of a projectile.

y=[tan(θ)](x)−(g)(x)^2/2(v0)^2cos^2(θ)

Where: y is the vertical displacement, x is the horizontal displacement, θis the launch angle, and g is the acceleration of gravity. v0 is the initial velocity.

Replacing known data:

y=tan(45°)(120ft)−(32.2ft/s^2)(120ft)^2/2(64ft/s)^2cos^2(45°)=6.8ft

y=6.8ft

The ball reaches the goal post at a height of 6.8 ft above the ground.

Answer 2

Answer:

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Explanation:

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