In a soccer practice session the football is kept at the center of the field 40 yards from the 10 ft high goalposts. A goal is attempted by kicking the football at a speed of 64 ft/s at an angle of 450 to the horizontal. Will the ball reach the goal post
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HI,
Solution:
g=9.8m/s2 =32.2ft /s2
40 yards=120 feet
Horizontal range =x=120 ft
u=64 ft/s
θ=45°
we know that horizontal range , x=u cosθ t
t=x/ucos θ
t=120/64 cos45 °
t=120 /64 x 1/√2
=120x 1.414/64
=2.65sec
y=sinθ(t)-1/2gt²
=sin(45) x 2.65 -1/2 (32.2)(2.65)²=7.08 ft which is less than the eight of goal post.
In time 2.65 sec the ball travels a horizontal distance 120ft and vertical height 7.08ft which is less than 10ft.
Hence the ball will reach the goal post.
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