Question

In a society ,6 children out of 28 did not participate in the campaign 'save energy ' . Find the probability that a child selected at ramdom (i) participate d in the campaign, (ii)did not participate the campaign. Which values of children are depicted here?

Answer 1

I) p(random selection)= 28-6= 22==>1/22
II)6/28==>3/14

Answer 2

Answer:

The probability that a child selected at random participate d in the campaign = $\frac{11}{14}$

The probability that a child selected at random did not participate d in the campaign = $\frac{3}{14}$

Step-by-step explanation:

Total children = 28

Children not participated = 6

Children participated = 28-6 =22

Now we are supposed to find that the probability that a child selected at random participate d in the campaign.

So,  the probability that a child selected at random participate d in the campaign = $\frac{22}{28}=\frac{11}{14}$

Now he probability that a child selected at random did not participate d in the campaign = $\frac{6}{28}=\frac{3}{14}$