Question

In a society campus, the playground is 160 m long and 80 m wide. In it 80 m × 80 m is kept for swings and in the remaining portion, there are 1.5 m wide path parallel to its width and parallel to its remaining length as shown in Figure. The remaining area is covered by grass. Find a) the area of the playground. b) the area of two roads. c) the area of the portion covered by grass.​

Answer 1

Answer:

Area of school playground is 160 m × 80 m = 12800 m2

Area kept for swings = 80 m × 80 m = 6400 m2

Area of path parallel to the width of playground = 80 m × 1.5 m = 120 m2

Area of path parallel to the remaining length of playground = 80 m × 1.5 m = 120 m2.

Area common to both paths = 1.5 m × 1.5 m = 2.25 m2. [since it is taken twice for measuerment it is to be subtracted from the area of paths]

Total area covered by both the paths

= (120 + 120 – 2.25) m2

= 237.75 m2.

Area covered by grass = Area of school playground – (Area kept for swings + Area covered by paths)

= 12800 m2 – [ 6400 + 237.75] m2

= (12800 – 6637.75) m2

= 6162.25 m2.