Question

In a society of 1250 families, 500 read news paper X, 300 read newspaper Y and 150 read both the newspapers. What is the number of families that read neither of the newspapers?​

Answer 1

Answer:

Ita help you

Step-by-step explanation:

We have S=120

i) The number of people who read exactly one newspaper

⇒P(H)+P(T)+P(I)−2((H∩T)+P(T∩I)+P(I∩H))+3P(H∩T∩I)

=50+52+52−2(18+22+16)+3(6)=60

ii) The number of people who read exactly two newspapers

⇒((H∩T)+P(T∩I)+P(I∩H))−3P(H∩T∩I)

=(18+22+16)−3(6)=38

iii) the number of people who read at least one of the newspapers

⇒P(H∪T∪I∪)=P(H)+P(T)+P(I)−((H∩T)+P(T∩I)+P(I∩H))+P(H∩T∩I)

=50+52+52−(18+22+16)+(6)=104