In a solid, oxide ions are arranged in CCP. Cations A occupy two-fifths of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is
a)A5B12018
b)A5B12015
c)A2B1204
d)A12B5015
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Answer:
The answer is d) A12B5O15.
Explanation:
O = 4
A = 2/5 × 8 = 16/5 ( TV = 8 )
B = 1/3 × 4 = 4/3 ( OV = 4 )
Formula of the compound = A16/5B4/3O4
= A48B20O60
= A12B5O15
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