in a solution 10% sodium chloride 25% glucose and the rest his water his present by mass calculate mole fraction of compound
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Answer:
Let the mass of solution is 100g
Then, mass of H
2
O=25g
mass of ethanol =25g
mass of acetic acid =50g
Number of moles of water =
18g/mol
25g
=1.4
Number of moles of ethanol =
46g/mol
25g
=0.54
Number of moles of Acetic acid =
60g/mol
50g
=0.8
Total number of moles =(1.4+0.54+0.8)=2.74
Now, mole fraction of water =
2.74
1.4
=0.51
mole fraction of Ethanol =
2.74
0.54
=0.197
mole fraction of acetic acid =
2.74
0.8
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