Question

In a solution 3.3 gram of non volatile solute is mixed in 125 gram of benzene find boiling point

Answer 1

Answer:

ANSWER

ΔTb=Kb×m

ΔTb=0.66=3.28K kg mol

−1

m=

Mb

Wb

×

Massofsolvent(kg)

1

m=

M

3.3

×

0.125

1

0.66=3.28(

M

3.3

×

0.125

1

)

M=131.20g