In a solution 3.3 gram of non volatile solute is mixed in 125 gram of benzene find boiling point
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ΔTb=Kb×m
ΔTb=0.66=3.28K kg mol
−1
m=
Mb
Wb
×
Massofsolvent(kg)
1
m=
M
3.3
×
0.125
1
0.66=3.28(
M
3.3
×
0.125
1
)
M=131.20g
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