In a solution,75% is orange juice and remaining is water. from this, if 20% is taken out, what will be the percentage of orange juice in the final solution?
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If the the initial volume = x
Volume of orange juice = 75%x
= 0.75x
20% of orange is removed, the remaining volume of orange = 80%
Volume of orange left = 80% * 0.75x
= 0.6x
The remaining volume of solution = x - 20%(0.75x)
= 0.85x
Percentage of orange in the final solution = 0.6x/0.85x * 100
= 70.588%
Volume of orange juice = 75%x
= 0.75x
20% of orange is removed, the remaining volume of orange = 80%
Volume of orange left = 80% * 0.75x
= 0.6x
The remaining volume of solution = x - 20%(0.75x)
= 0.85x
Percentage of orange in the final solution = 0.6x/0.85x * 100
= 70.588%
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Answer:
Step-by-step explanation:
If the the initial volume = x
Volume of orange juice = 75%x
= 0.75x
20% of orange is removed, the remaining volume of orange = 80%
Volume of orange left = 80% * 0.75x
= 0.6x
The remaining volume of solution = x - 20%(0.75x)
= 0.85x
Percentage of orange in the final solution = 0.6x/0.85x * 100
= 70.588%
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