In a solution the concentrations of CaCl2 is 5M & that of MgCl2 is 5m. The specific gravity of solution is 1.05, calculate the concentration of Cl ions in the solution in terms of molarity.
Answers
Answered by
8
1 mole of CaCl2 has 2 moles of Cl-
5 moles of CaCl2 has = 2x5 = 10 moles of Cl-
1 mole of MgCl2 has 2 moles of Cl-
5 moles of MgCl2 has = 2x5 = 10 moles of Cl-
Total number of moles of Cl- = 10 + 10
= 20 moles
The concentration of Cl ions in the solution in terms of molarity
= 20M
5 moles of CaCl2 has = 2x5 = 10 moles of Cl-
1 mole of MgCl2 has 2 moles of Cl-
5 moles of MgCl2 has = 2x5 = 10 moles of Cl-
Total number of moles of Cl- = 10 + 10
= 20 moles
The concentration of Cl ions in the solution in terms of molarity
= 20M
Answered by
11
see attachment listed below
Attachments:
Similar questions
Math,
7 months ago
Math,
7 months ago
Math,
7 months ago
Computer Science,
1 year ago
Science,
1 year ago