In a solution the concentrations of CaCl2 is 5M & that of MgCl2 is 5m. The specific gravity of solution is 1.05, calculate the concentration of Cl ions in the solution in terms of molarity.
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1 mole of CaCl2 has 2 moles of Cl-
5 moles of CaCl2 has = 2x5 = 10 moles of Cl-
1 mole of MgCl2 has 2 moles of Cl-
5 moles of MgCl2 has = 2x5 = 10 moles of Cl-
Total number of moles of Cl- = 10 + 10
= 20 moles
The concentration of Cl ions in the solution in terms of molarity
= 20M
5 moles of CaCl2 has = 2x5 = 10 moles of Cl-
1 mole of MgCl2 has 2 moles of Cl-
5 moles of MgCl2 has = 2x5 = 10 moles of Cl-
Total number of moles of Cl- = 10 + 10
= 20 moles
The concentration of Cl ions in the solution in terms of molarity
= 20M
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