Question

in a spectrometer experiment monochromatic light is incident normally on a diffraction grating having 4.5 into 10 power 5 lines per metre the second order line is seen at an angle of 30 degree to the normal what is the wavelength of the light approx​

Answer 1

                                                                                                               

$Answer :$ $556 nm$

                                                                                                               

$solution :$

The angle of diffraction θ normal to the grating for nth order diffraction pattern is given by  dsinθ=nλ

Where d is the spacing of the slits

λ is the wavelength of the source.

now , $d=\frac{1}{4.5 * 10^5 }m$, θ=30 and n=2

We thus have

λ = $\frac{dsin}{n}$ = $\frac{sin30}{2(4.5*10^5)} =566nm$

                                                                                                               

hope it help you mark brainliest and said thank

Answer 2

Answer:

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Explanation:

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