In a sphere , Radius = 7 cm
FIND (A) T.S.A =
In case of hemisphere , radius = 3.5
FIND (A) C.S.A =
(B) T.S.A =
(FIND VALUE IN TERMS OF Π) (NOT PUT VALUE OF Π) plz step by step
Answers
Step-by-step explanation:
1. T.S.A of sphere = 4πr square
= 4 * π * 49
= 196π.
2. T.S.A of hemisphere = 3πr square
= 3*π*12.25
= 36.75π.
3. C.S.A of hemisphere = 2πr square
=2 * π * 12.25
= 24.5π.
Solution 1 :-
Given :-
- In a sphere , Radius = 7 cm.
To Find :-
- TSA of Sphere = ?
Answer :-
- TSA of Sphere = 196 π
Explaination :-
→ TSA of Sphere = 4πr²
→ TSA of Sphere = 4π(7)²
→ TSA of Sphere = 4π(49)
→ TSA of Sphere = 196 π
Therefore,TSA of Sphere is 196 π.
Solution 2 :-
Given :-
- In case of hemisphere , radius = 3.5
To Find :-
- CSA of hemisphere = ?
- TSA of hemisphere = ?
Answer :-
- CSA of hemisphere = 24.5π
- TSA of hemisphere = 36.75π
Explaination :-
→ CSA of hemisphere = 2πr²
→ CSA of hemisphere = 2π(3.5)²
→ CSA of hemisphere = 2π(12.25)
→ CSA of hemisphere = 24.5π
→ TSA of hemisphere = 3πr→²
→ TSA of hemisphere = 3π(3.5)²
→ TSA of hemisphere = 3π(12.25)
→ TSA of hemisphere = 36.75 π
Hence,
- CSA of hemisphere = 24.5π
- TSA of hemisphere = 36.75 π