Math, asked by shubhamChauhan11, 1 year ago

In a sports club there are 1200 members. The club has facilitics for only three types of sports- tennis, swimming and billiards. 880 members play tennis, 690 have joined swimming, 675 play billiards, 430 play both tennis and swimming, 345 do both swimming and play billiards, 460 play both billiards and tennis. 190 play all the three games. How many play two or more games!

Answers

Answered by singhrasna414
5

Answer:

answer is 855

Step-by-step explanation:

430-190=240

345-190=155

460-190=270

now 240+155+270+190(play the all games)=855

Answered by orangesquirrel
0

Given:

Total members = 1200

Members playing all three= 190

Members playing tennis= 880

Members joined swimming= 690

Members playing billiards= 675

Members playing both tennis and swimming= 430

Members playing both billiards and swimming= 345

Members playing both billiards and tennis= 460

To find:

Members playing two or more games

Solution:

So, members playing only tennis and swimming= 430-190= 240

Members playing only billiards and swimming= 345-190= 155

Members playing only billiards and tennis= 460-190= 270

So, members playing only two games= 240+155+270= 665

So, members playing two or more games= Members playing only two games+ Members playing all the three games = 665+190= 855

Members playing two or more games is 855.

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