Question

In a square abcd ab-(2x +3) cm and bc-(3x -5) cm find the value of x

Answer 1

Given :----

• ABCD is a Square
• side AB = 2x+3
• side BC = 3x-5

To Find :----

• value of x ?

concept used :----

• All sides of square are Equal in length ..

solution :----

putting all both we get,

(2x-3) = (3x -5)

→ 2x - 3x = -5 +3

→ -x = -2

→ x = 2 (Ans)

Hence , value of x is 2 ..

(Hope it helps you)

Answer 2

$\huge\boxed{\mathfrak{\red{Answer}}}$

ABCD is a square

Given :- Side A B =(2x+3)

And Side BC =(3x-5)

Now according to question we know that the all sides of square are equal

Then we write as

AB=BC

$\sf (2x+3)=(3x-5)\\ \sf 2x+3=3x-5\\ \sf 3+5=3x-2x\\ \sf 8=x \\ \sf or x=8$

$\huge\boxed{\mathfrak{Verification}}$

Put the value of x which is 8

$\sf 2×8+3=3×8-5\\ \sf 16+3=24-5\\ \sf 19=19$

L.H.S =R.H.S verified! !

$\huge\boxed{\mathfrak{\red{x=8}}}$