in a square ABCD ,ab-(2x+5) cm and bc -(3x-5) cm. then ,the vaule of x
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in a square all sides are equal so
-(2x+5)=(3x-5)
-2x-5=3x-5
-2x-3x=-5+5
-5x=0
x=0/-5
x=0
Answered by
0
Answer:
I think this is correct answer.
(2x+5) = (3x-5)
2x+3x = +5-5
5x = 0
x = 0/5
x = 0
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