In a square ABCD, AB = (5x – 44) cm and BC = (2x – 5) cm. Find the (i) length AD (ii) length AC.
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EXPLANATION:
Since it is a square,
AB=BC
5x – 44 = 2x – 5
5x – 2x = 44 – 5
3x = 39
x = 13
So, AB = 5 x 13 – 44
AB = 21cm
1) AD = 21 cm
Now, AC is the diagonal and Triangle ABC is a right triangle
So, AC² = AB² + BC ²
AC² = 21² + 21²
AC² = 882
AC = √882
AC = 21√2
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