in a square abcd,ab|| dc,ab= 25 bc = 10cm
length of non parallel sides, AD and BC are 14cm and 15cm respectively. Find area of square ABCD?
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trapezium ABCD
AB∥CD,
AB=30cm and CD=44cm, AD=13cm,BC=15cm.
semi-perimeter =
2
30+44+13+15
=51
area of trapezium =
(s−a)(s−b)(s−a−c)(s−a−d)
⋅
(b−a)
(a+b)
where a and b are two parallel sides and b > a and c and d are non-parallel sides
s=
2
a+b+c+d
=51
area of trapezium ABCD=
44−30
30+44
⋅
(51−30)⋅7(51−30−13)⋅(51−30−15)
=
14
74
⋅
21⋅7⋅8⋅6
=
7
37
⋅7
3⋅3⋅2⋅8
=37×3×4=37×12=444cm
2
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