Question

In a square ABCD, AC = (7x - 2) cm and
BD = (Ilx-10) cm. AC is equal to :​

Answer 1

Step-by-step explanation:

Question:-

In a square ABCD, AC = (7x - 2) cm and

In a square ABCD, AC = (7x - 2) cm andBD = (Ilx-10) cm. AC is equal to ?

Solution:-

As we know in a square all sides are equal

${:}\longrightarrow$$\overline {AC}={\overline{BD}}$

${:}\longrightarrow$$7x-2=11x-10$

${:}\longrightarrow$$7x-11x=-10+2$

${:}\longrightarrow$$-4x=-8$

${:}\longrightarrow$$4x=8$

${:}\longrightarrow$$x={\frac{8}{4}}$

${:}\longrightarrow$${\underline{\boxed {\sf{x=2}}}}$

AC=7x-2

${:}\longrightarrow$7 (2)-2

${:}\longrightarrow$14-2

${:}\longrightarrow$12cm

${:}\longrightarrow$${\underline{\boxed{\bf {{\overline{AC}}=12cm}}}}$