In a square abcd, if cd= 8 cm, find the diagonal of the square?
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Answer:
one side of square is given 8cm
so all its sides become 8 cm
now if join the diagonal of the square,it forms a right triangle, therefore we can apply Pythagoras theorem,
h^2=p^2+b^2
BD^2=8^2+8^2
BD^2=64+64
BD^2= (8√2)^2
BD=8√2 cm
or BD = 8×1.414cm
BD=11.312cm (approx)
there is an alternative method for this
use the formula diagonal of square =✓2×side
=√2×8
8√2cm
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