in a square ABCD, in diagonal AC=(3x+1) units and BD=(X+7) units. the perimeter of square is
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Answer:
3x+1=x+7
2x=6
x=3
let side of square = a
root 2 × a= diagonal{by Pythagorean theorem}
from this a=3/root 2
perimeter of square = 4a
=4×3/root 2
=6root2
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