Question

In a square ABCD, the diagonals AC and BD intersect at O.The measure of angle OBC is

options :

1 - 0°
2 - 45°
3 - 90°
4 - 120°
​

Answer 1

Answer:

OA = OB { diagonals of parallelogram

bisect each other.}

angle OAB = angle OBA

{ opposite angles of

equal sides are equal}

angle COD = angle AOB { vertically

opposite angle}

In ∆OAB,

angle AOB + OAB + OBA = 180°

angle AOB + 2 ( OAB ) = 180°

120° +2( angle OAB) = 180

angle OAB = 60°/2

angle OAB = 30°

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mark as brainliest answer.

Answer 2

Answer:

he said like this I not understand anything some people are in your life and some are in your memories

Step-by-step explanation:

what happened in both of you I am totally confused

but you not answer to my question when you will come to chintu's house