in a square in a square ABCD a b is equal to 3 x minus 7 cm and BC =(x+3)cm find the length of a d
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Sides are AB , BC , CA , AD
Given AB = ( 3x - 7 ) cm
BC = ( x + 3 ) cm
We know, all sides are equal in square
So, AB = BC
=> ( 3x - 7 ) = (x + 3 )
=> 3x - 7 = x + 3
=> 3x - x = 3 + 7
=> 2x = 10
=> x = 5
Hence,AB = BC = x + 3 = 5 + 3 = 8 cm
Now, By Pythagoras theorem,
Diagonal = AD
side^2 + side^2 = diagonal^2
8^2 + 8^2 = diagonal ^2
2(8)^2 = diagonal
8√2 cm = diagonal = AD
Given AB = ( 3x - 7 ) cm
BC = ( x + 3 ) cm
We know, all sides are equal in square
So, AB = BC
=> ( 3x - 7 ) = (x + 3 )
=> 3x - 7 = x + 3
=> 3x - x = 3 + 7
=> 2x = 10
=> x = 5
Hence,AB = BC = x + 3 = 5 + 3 = 8 cm
Now, By Pythagoras theorem,
Diagonal = AD
side^2 + side^2 = diagonal^2
8^2 + 8^2 = diagonal ^2
2(8)^2 = diagonal
8√2 cm = diagonal = AD
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