In a square one diagonal is 16 cm . Find its sides
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Let the length of Side = x
Therefore by pythagoras theorem, length of diagonal = (x^2 + x^2)^0.5
Length of diagonal = x× (2^0.5)
16 = x (2^0.5)
x = 16/(2^0.5)
x = 11.3137.... cm (approx)
Therefore by pythagoras theorem, length of diagonal = (x^2 + x^2)^0.5
Length of diagonal = x× (2^0.5)
16 = x (2^0.5)
x = 16/(2^0.5)
x = 11.3137.... cm (approx)
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