Question

In a square shaped park of side 25 m, a rectangular sand pit 3m by 2m is located. What is the area of the park around the sand pit?
619 sq m
19 sq m
631 sq m

Answer 1

Answer:

631 sq m

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Answer 2

Given:-

• Side of a square park = 25 m.
• Dimensions of the sand pit: Length = 3 m and Breadth = 2 m.

To find:-

• The area of the park excluding the sand pit.

Formulae used:-

• Area of square = s² sq.units
• Area of rectangle = lb sq.units

Solution:-

According to the question, the sandpit is located inside the park. So, the area excluding the sand pit can be found by subtracting the area of sand pit from the total area of the park. Let's find it !!

$\:$

↪Area of the square park:

• On substituting the measures,

$\\\:\:\:\:\:\:\:\:\:\:\:\leadsto{\textbf{\textsf{\purple{s ^2 \:sq.units}}}}$

$\\\:\:\:\:\:\:\:\:\:\:\:\implies{\sf{(25)^2}}$

$\\\:\:\:\:\:\:\:\:\:\:\:\implies{\sf{25\times 25}}$

$\\\:\:\:\:\:\:\:\:\:\:\:\implies\underline{\bf{625\:m^2}}$

$\:$

↪Area of sand pit:

• On substituting the measures,

$\\\:\:\:\:\:\:\:\:\:\:\:\leadsto{\textbf{\textsf{\purple{lb\:sq.units}}}}$

$\\\:\:\:\:\:\:\:\:\:\:\:\implies{\sf{3\times 2}}$

$\\\:\:\:\:\:\:\:\:\:\:\:\implies\underline{\bf{6\:m^2}}$

$\:$

↪Area of the park around the sand pit:

Now, we know the areas of the park and the sandpit. Consequently, we can find the area excluding the sand pit of the park by subtracting 6 m² from 625 m², i.e.,

$\\\:\:\:\:\:\:\:\:\:\:\:\implies{\sf{625-6}}$

$\\\:\:\:\:\:\:\:\:\:\:\:\implies{\boxed{\boxed{\frak{\red{619\:m^2}}}}}$

$\\ \therefore\underline{\sf{The\:area\:of\:the\:park\:around\:the\:sand\:pit\:is\:\textbf{\textsf{\pink{619\:m ^2 \:(Opt:a)}\sf{.}}}}}$

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