Math, asked by shraddha1732, 1 year ago

In a staircase, there ar 10 steps. a child is attempting to climb the staircase. each time she can either make 1 step or 2 steps. in how many different ways can she climb the staricase?

Answers

Answered by Shubhendu8898
21

Number  of ways  if  he goes  by  'one step' = 1

Number  of ways  of choosing    1  'two step' in  9 moves = 9C1 = 9

Number  of ways  of  choosing  2  'two steps in 8 moves = 8C2 = 28

Number  of ways  of  choosing  3 'two steps' in 7 moves = 7C3 = 35

Number  of ways  of  choosing  4 'two steps' in 6 moves =  6C4 = 15

Number  of ways  of  choosing 5  'two steps' in 5 moves = 5C5 = 1

Total Number  of  ways = 1 + 9 + 28 + 35 + 15 + 1 = 89

Answered by imhkp4u
18

Acc to the question, In a staircase, there ar 10 steps. a child is attempting to climb the staircase. each time she can either make 1 step or 2 steps.


There are two methods for solving this question. Firstly, you can use the general permutaion and combination and secondly you can also use the fibo series but the starting two terms as 1, 2.


If you follow the question carefully, then the number of ways will nothing but a fibonacci series for n=10.

Fibo series: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233........

Thus, the 10th term of the series will be 89.

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