Question

In a standing wave two points are separated by 4 cm, if speed of wave is 330 metre per second and frequency is 110 Hz then find phase difference between those two points​

Answer 1

Explanation:

Phase difference =

λ

2π

×path difference.

The phase difference between any two particles in a wave determines lack of harmony in the vibrating state of two particles ie, how far one particle leads the other or lags behind the other.

From relation

Δϕ=

λ

2π

×δx

⇒Δx=

2π

λ

×Δϕ ...(i)

Also, λ=

n

v

...(ii)

Now, from Eqs. (i) and (ii), we get

Δx=

2πn

v

×Δϕ

⇒Δx=

2π×50

330

×

3

pi

or Δx=1.1m