Math, asked by pankajkantinath, 10 months ago

In a statistical investigation of 1003 families of Chandigarh it was found that 63 families has neither a phone nor a TV, 794 families has none and 187 has a TV. the number of families in that group having both a phone and a TV

Answers

Answered by knjroopa
0

Step-by-step explanation:

Given In a statistical investigation of 1003 families of Chandigarh it was found that 63 families has neither a phone nor a TV, 794 families has none and 187 has a TV. the number of families in that group having both a phone and a TV

  • Now we have from the union formula for any finite sets for the number of elements A and B
  • So n(A U B) = n(A) + n(B) – n(A Ո B)
  • Now number of families are 1003
  • So families having either phone or T.V = 63
  •                So 1003 – 63 = 940
  • So applying the above equation we get  
  • (since n(A) = 794 and n(B) = 187) we get
  • 940 = 794 + 187 – n (A Ո B)
  • 940 = 981 – n(A Ո B)
  • Or n(A Ո B) = 981 – 940
  •                     = 41
  • So the number of families having both phone and TV is 41

Reference link will be

https://brainly.in/question/7439597

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