Question

In a step up transformer (efficiency 90%), the output voltage is 200 V. If input power and voltage are 2 kW and 150 V, then the current in secondary coil is​

Answer 1

Answer:

follow the attachment ☺️

Explanation:

hope it will help you

Answer 2

Answer:

The current in secondary coil is​ 9A.

Explanation:

In step up transformer,

Efficiency, η% = $\frac{e_{s} i_{s}} {e_{p}i_{p} }$

90 = $\frac{200\times i_{s} }{\frac{2000}{150} 150}$

Solving the equation,

$i_{s}$ = 9 A

The correct answer is 9 A.