In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% moisture, by weight. After two days in the sun, the moisture content of the berries was only 98%, by weight. What was the total weight of the berries after two days, in kg?
Answers
Required Answer:-
Total weight of the berries initially was 200 kg. And it was 99% full of moisture. Then 1% other substances.
That is,
1% of 200 kg = 2 kg
Now after drying in the sun, moisture content is 98%. Then rest substances is 2%. That means, 2 kg is 2% of total weight of watermelon now..
Hence,
➛ 2% of total weight now = 2 kg
➛ 2/100 × Total weight now = 2 kg
➛ Total weight now = 100 kg.
Therefore,
Total weight of the berry after two days will be 100 kg.
Answer:
Total weight of the berries initially was 200 kg. And it was 99% full of moisture. Then 1% other substances.
That is,
1% of 200 kg = 2 kg
Now after drying in the sun, moisture content is 98%. Then rest substances is 2%. That means, 2 kg is 2% of total weight of watermelon now
Hence,
➛ 2% of total weight now = 2 kg
➛ 2/100 × Total weight now = 2 kg
➛ Total weight now = 100 kg.
Therefore,
Total weight of the berry after two days will be 100 kg.