Question

In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% moisture, by weight. After two days in the sun, the moisture content of the berries was only 98%, by weight. What was the total weight of the berries after two days, in kg?​

Answer 1

$\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

Data provided in the question:

Initial total weight of the berries = 200 kg Initial weight of water present = 99% of the

weight

= 198 kg

therefore,

Initial weight of the solids in berries = 200 kg -

198 kg = 2 kg

After 2 days water was 98% of the total weight of the berries

Thus,

2% was solid which means 2 kg was 2% of the total weight of the berries

Thus,

2% of Total weight of berries after two days = 2

kg

or

0.02 x Total weight of berries after two days = 2

kg

or

Total weight of berries after two days = [ 2 :

0.02 ] kg

or

Total weight of berries after two days = 100 kg

Answer 2

$\huge\bf{\underline{\overline{\pink{Solution :}}}}$

Total weight of the berries initially was 200 kg. And it was 99% full of moisture. Then 1% other substances.

That is,

• 1% of 200 kg = 2 kg

Now after drying in the sun, moisture content is 98%. Then rest substances is 2%. That means, 2 kg is 2% of total weight of watermelon now.

Hence,

➛ 2% of total weight now = 2 kg

➛ 2/100 × Total weight now = 2 kg

➛ Total weight now = 100 kg.

Therefore,

Total weight of the berries after two days will be $\bold{100 kg.}$