In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% moisture, by weight. After two days in the sun, the moisture content of the berries was only 98%, by weight. What was the total weight of the berries after two days, in kg?
Answers
Data provided in the question:
Initial total weight of the berries = 200 kg Initial weight of water present = 99% of the
weight
= 198 kg
therefore,
Initial weight of the solids in berries = 200 kg -
198 kg = 2 kg
After 2 days water was 98% of the total weight of the berries
Thus,
2% was solid which means 2 kg was 2% of the total weight of the berries
Thus,
2% of Total weight of berries after two days = 2
kg
or
0.02 x Total weight of berries after two days = 2
kg
or
Total weight of berries after two days = [ 2 :
0.02 ] kg
or
Total weight of berries after two days = 100 kg
Total weight of the berries initially was 200 kg. And it was 99% full of moisture. Then 1% other substances.
That is,
- 1% of 200 kg = 2 kg
Now after drying in the sun, moisture content is 98%. Then rest substances is 2%. That means, 2 kg is 2% of total weight of watermelon now.
Hence,
➛ 2% of total weight now = 2 kg
➛ 2/100 × Total weight now = 2 kg
➛ Total weight now = 100 kg.
Therefore,
Total weight of the berries after two days will be