Question

In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% moisture, by weight. After two days in the sun, the moisture content of the berries was only 98%, by weight. What was the total weight of the berries after two days, in kg?​

Answer 1

Data provided in the question:

Initial total weight of the berries = 200 kg Initial weight of water present = 99% of the weight

= 198 kg

therefore,

Initial weight of the solids in berries = 200 kg - 198 kg = 2 After 2 days water was 98% of the total weight of the

kg

berries

Thus,

2% was solid which means 2 kg was 2% of the total weight of the berries

Thus,

2% of Total weight of berries after two days = 2 kg

or

0.02 x Total weight of berries after two days = 2 kg

or

Total weight of berries after two days = [2 + 0.02 ] kg

or

Total weight of berries after two days = 100 kg

Explanation:

Answer 2

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• Total weight of the berries initially was 200 kg. And it was 99% full of moisture. Then 1% other substances.

That is,

1% of 200 kg = 2 kg

Now after drying in the sun, moisture content is

98%. Then rest substances is 2%. That means, 2

kg is 2% of total weight of watermelon now..

Hence,

➛ 2% of total weight now = 2 kg

➛ 2/100 × Total weight now = 2 kg

➛ Total weight now = 100 kg.

Therefore,

Total weight of the berry after two days will be 100 kg.