Question

In a store window, there was a box of berries having a total weight of 200 kg. The berries were 99% moisture, by weight. After two days in the sun, the moisture content of the berries was only 98%, by weight. What was the total weight of the berries after two days, in kg?​

Answer 1

Answer:

you have 100 kg of berries and they are 99% water and 1% berry fruit

1% of 100 kg=1 kg of berry fruit

the weight now of the berries is made up of 98% water which means that 2% is berry fruit

the amount of berry fruit does not change; it neither increases nor decreases, only the amount of water changes

you have 1 kg of berry fruit which makes up 2% of the total weight

2% of what number equals 1 kg ?

2%*n=1

0.02*n=1

n=1/0.02

n=100/2

n=50 kg total weight (2% of 50=1 !!!) Hard to believe that if you lose 1% of water you lose 50 kg of weight.

Here's a simple way of doing the problem...

original weight was 99% water or 99/100

now we have 98% water or 98/100 which simplifies to 49/50; 49 kg of water and 1 kg of berry fruit

check:98%*50=49 and 2%*50=1 (remember we had 1 kg of berry fruit which did not change

Explanation:

Please mark me as a brainly star⭐⭐⭐

Answer 2

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• Total weight of the berries initially was 200 kg. And it was 99% full of moisture. Then 1% other substances.

That is,

1% of 200 kg = 2 kg

Now after drying in the sun, moisture content is

98%. Then rest substances is 2%. That means, 2

kg is 2% of total weight of watermelon now..

Hence,

➛ 2% of total weight now = 2 kg

➛ 2/100 × Total weight now = 2 kg

➛ Total weight now = 100 kg.

Therefore,

Total weight of the berry after two days will be 100 kg.