Math, asked by kavitamourya8251, 1 year ago

In a stream running at 2 kmph, a motorboat goes 6 km upstream and back again to the starting
point in 33 minutes. Find the speed of the motorboat in still water.

Answers

Answered by arc555
11

Let the speed of the motorboat in still water be x kmph.

Then, speed downstream = (x + 2) kmph.

Speed upstream = (x - 2) kmph.

:. 6/(x + 2) + 6/(x - 2) = 33/60 0r 11X2 –

240x – 44=0

11X2 – 242X + 2X –44 =0 or 11x(x – 22) + 2(x – 22) = 0

or (x-22)(11x+2)=0 or x=22.

:. Speed of motorboat in still water = 22 kmph.

Answered by sourasghotekar123
2

Answer:

Speed of motorboat in still water = 22 kmph.

Step-by-step explanation:

As per the data given in the question,

we have,

Lets assume speed of the motorboat in still water be x kmph.

So, speed downstream = (x + 2) kmph.

Speed upstream = (x - 2) kmph.

Distance travelled in one round = 6 km

As, time=distance/time

So, upstream time + downstream time = total time

\frac{6}{(x + 2)}+ \frac{6}{(x - 2)} = \frac{33}{60}\\ 11\times2-240x - 44=011x^{2}  -242x + 2x -44 =0 \\ 11x(x - 22) + 2(x - 22) = 0\\(x-22)(11x+2)=0

ss, x=22 or x= -2/11. Since negative speed is not possible so,

Speed of motorboat in still water = 22 kmph.

#SPJ2

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