Question

In a string the speed of wave is 10 m/s and itsfrequency is 100 Hz. The value of the phasedifference at a distance 25 cm will be​

Answer 1

The phase difference is $2\pi$.

Explanation:

Given that,

Speed of the wave, v = 10 m/s

Frequency of the wave, f = 100 Hz

To find,

The value of the phase difference at a distance 25 cm will be​:

Solution,

The speed of a wave is given by :

$v=f\lambda$

$\lambda=\dfrac{v}{f}$

$\lambda=\dfrac{10\ m/s}{100\ Hz}$

$\lambda=0.1\ m$

It implies that $2\pi$ radian is phase is covered in 0.1 m. So, 25 cm or 0.25 m of the phase difference is covered in :

$\phi=\dfrac{2\pi \times 0.25}{0.1}$

$\phi=5\pi$

So, the phase difference is $2\pi$.

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