Question

In a study about the male and female students of commerce and science departments of a

college in 5 years, the following datas were obtained :

1995 2000

70% male students 75% male students

65% read Commerce 40% read Science

20% of female students read Science 50% of male students read Commerce

3000 total No. of students 3600 total No. of students.

After combining 1995 and 2000 if x denotes the ratio of female commerce student to

female Science student and y denotes the ratio of male commerce student to male Science

student, then

(a) x = y (b) x > y (c) x < y (d) x  y​

Answer 1

Step-by-step explanation:

1995

70% male students = 2100 (70% of 3000)

30% female students = 900

65% read commerce = 1950

35% read science =1050

20% of female read science =180

80% of female read commerce = 720

Male students read commerce =1230 (1950 - 720)

Male students read science = 870

2000:-

75% male students = 2700 (75% of 3600)

25% female students = 900

40% read science = 1440

60% read commerce = 2160

50% of male students read commerce = 1350

50% of male students read science = 1350

Famale students of science = 90

Female students of commerce = 810

x= female commerce student / female science students = 720+810/180+90= 1530/270 = 5.666...

y= male commerce students / female commerce students = 1230+1350/870+1350 = 2580/2220 = 1.162162....

x>y hence proved => 5.6>1.162

Please mark it as a "BRAINLIEST" Answer ✌

Answer 2

Concept:

The question is in caselet form which is a set of information which is given in the paragraph form.

Given:

We have given the data of students in $1995$ and $2000$ in which the total number of students in $1995$ is $3000$ and in $2000$ is $3600$.

Find:

We need to estimate the correct relation for $x$ and $y$ as per the given option.

Solution:

Considering the data for the students in $1995$

Total number if students $=3000$

Number of male students = 70% $=\frac{70}{100}\times3000=2100$

so female students is $3000-2100=900$

$65$% students read commerce $=\frac{65}{100} \times3000=1950$

$20\%$ of female read science $=\frac{20}{100} \times 900=180$

Concluding from the above information

               Science          Commerce

male-        330                    1770

female-     720                    180

Now, considering the data for students in $2000$

Total number of students $=3600$

Number of male students $=75\%=\frac{75}{100} \times3600=2700$

so the number of female students $=3600-2700=900$

$40\%$ of students read science $=\frac{40}{100} \times3600=1440$

$50\%$ of male read commerce $=\frac{50}{100}\times2700=1350$

Concluding from the above data

               Science          Commerce

male-        1350                  1350

female-     90                     810

Combining the data of $1995$ and $2000$ as required by the question

Number of male students of science $=330+1350=1680$

Number of male students of commerce $=1770+1350=3120$

Number of female students of science $=720+90=810$

Number of male students of commerce $=180+810=990$

Now, from the question $x$ denotes the ratio of female commerce students to female Science student

$x=\frac{990}{810} =\frac{11}{9}=1.02$

and $y$ denotes the ratio of male commerce students to male Science

$y=\frac{3120}{1680}=\frac{13}{7}=1.08$

We can see that $x > y$.

Hence, option (b) Is the correct option.