Math, asked by ayushi5155, 4 months ago

. In a study of number of accidents per day, the observations for 30 days were obtained as follows:
6.3. 5. 6. 4. 3. 2, 5, 4, 2, 4, 2, 1, 2, 2.
0,5, 4, 6, 1,6, 0,5, 3, 6, 1, 5, 5, 2,6
Prepare a frequency distribution table,​

Answers

Answered by TH3808
2

Answer:

Let total rations be P kg.

Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.

ration used in 12 days=12*p/60=p/5 kg

ration left= 4p/5

Let the number of days be d.

Now, number of students is 800.

So, ration per day per student= (4p/5)/(800*d)

p/(60*500)=(4p/5)/800*d

Therefore d=30.

The remaining rations will last for 30 days

Step-by-step explanation:

Let total rations be P kg.

Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.

ration used in 12 days=12*p/60=p/5 kg

ration left= 4p/5

Let the number of days be d.

Now, number of students is 800.

So, ration per day per student= (4p/5)/(800*d)

p/(60*500)=(4p/5)/800*d

Therefore d=30.

The remaining rations will last for 30 daysLet total rations be P kg.

Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.

ration used in 12 days=12*p/60=p/5 kg

ration left= 4p/5

Let the number of days be d.

Now, number of students is 800.

So, ration per day per student= (4p/5)/(800*d)

p/(60*500)=(4p/5)/800*d

Therefore d=30.

The remaining rations will last for 30 daysLet total rations be P kg.

Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.

ration used in 12 days=12*p/60=p/5 kg

ration left= 4p/5

Let the number of days be d.

Now, number of students is 800.

So, ration per day per student= (4p/5)/(800*d)

p/(60*500)=(4p/5)/800*d

Therefore d=30.

The remaining rations will last for 30 daysLet total rations be P kg.

Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.

ration used in 12 days=12*p/60=p/5 kg

ration left= 4p djskj/5

Let the number of days be d.

Now, number of students is 800.

So, ration per day per student= (4p/5)/(800*d)

p/(60*500)=(4p/5)/800*d

Therefore d=30.

The remaining rations will last for 30 days

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