. In a study of number of accidents per day, the observations for 30 days were obtained as follows:
6.3. 5. 6. 4. 3. 2, 5, 4, 2, 4, 2, 1, 2, 2.
0,5, 4, 6, 1,6, 0,5, 3, 6, 1, 5, 5, 2,6
Prepare a frequency distribution table,
Answers
Answer:
Let total rations be P kg.
Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.
ration used in 12 days=12*p/60=p/5 kg
ration left= 4p/5
Let the number of days be d.
Now, number of students is 800.
So, ration per day per student= (4p/5)/(800*d)
p/(60*500)=(4p/5)/800*d
Therefore d=30.
The remaining rations will last for 30 days
Step-by-step explanation:
Let total rations be P kg.
Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.
ration used in 12 days=12*p/60=p/5 kg
ration left= 4p/5
Let the number of days be d.
Now, number of students is 800.
So, ration per day per student= (4p/5)/(800*d)
p/(60*500)=(4p/5)/800*d
Therefore d=30.
The remaining rations will last for 30 daysLet total rations be P kg.
Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.
ration used in 12 days=12*p/60=p/5 kg
ration left= 4p/5
Let the number of days be d.
Now, number of students is 800.
So, ration per day per student= (4p/5)/(800*d)
p/(60*500)=(4p/5)/800*d
Therefore d=30.
The remaining rations will last for 30 daysLet total rations be P kg.
Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.
ration used in 12 days=12*p/60=p/5 kg
ration left= 4p/5
Let the number of days be d.
Now, number of students is 800.
So, ration per day per student= (4p/5)/(800*d)
p/(60*500)=(4p/5)/800*d
Therefore d=30.
The remaining rations will last for 30 daysLet total rations be P kg.
Given, the rations are sufficient for 60 days. So, the ration used in one day is p/60 kg. This is for students. So, the ration used per day per student is p/(60*500) kg.
ration used in 12 days=12*p/60=p/5 kg
ration left= 4p djskj/5
Let the number of days be d.
Now, number of students is 800.
So, ration per day per student= (4p/5)/(800*d)
p/(60*500)=(4p/5)/800*d
Therefore d=30.
The remaining rations will last for 30 days