in a submarine fitted with a sonar ,the time interval between the generation of an ultrasonic wave and the time receipt of its eco is 200s. what is the distnace of the enemy submarine? the speed of sound in water is 1.450 kms-1
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Answered by
79
Hi dear
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Suppose that the distance from enemy sub - marine = x
Then , The Total distance covered by wave in water = 2x
We know , Velocity = Distance / Time
ATQ ,
Velocity of sound wave × time = total distance covered by sound wave in water
1450 × 200 = 2x
x = 1450 × 200 / 2
= 1450 × 100
= 145000 m = 145 km
____________________________________________________________
Suppose that the distance from enemy sub - marine = x
Then , The Total distance covered by wave in water = 2x
We know , Velocity = Distance / Time
ATQ ,
Velocity of sound wave × time = total distance covered by sound wave in water
1450 × 200 = 2x
x = 1450 × 200 / 2
= 1450 × 100
= 145000 m = 145 km
Answered by
9
the distance from enemy sub - marine = x
Then , The Total distance covered by wave in water = 2x
We know , Velocity = Distance / Time
ATQ ,
Velocity of sound wave × time = total distance covered by sound wave in water
1450 × 200 = 2x
x = 1450 × 200 / 2
= 1450 × 100
= 145000 m = 145 km
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