Question

in a submarine the time interval from emission to detection of sound pulse is found to be 77 seconds what is the distance of Enemy summary if the speed of the sound in water is 1450 metre per second....... in this question why we divide 77 by 2 ​

Answer 1

Answer:

because formula is v=2dt and we find out d then formula is d =vt/2 that why divided by 2

Explanation:

Given,

v = 1460 m/s , t = 77 sec

∴ d = vt/2 = 1460 × 77/2 = 1460 × 38.5 = 56210 m = 56.21 km

Hence , distance of enemy submarine = 56.21 km

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