In a summer storm, the wind is blowing with a velocity of 8 m/'s north. Suddenly in 3 seconds, the winds velocity is 23 m/s north. What us the Acceleration?
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Initial velocity (u) => 8m/s
Final velocity(v) => 23m/s
Time taken (t) => 3 s
Let acceleration be a
According to formula, v = u + at
a = (v-u)/t
=> (23-8)/3
=> 5 m/s2
Answered by
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Heya mate,
Here is your answer,.⬇️⬇️
_________
The wind was blowing at 8 m/s.
In 3 seconds, it blows with a velocity 23 m/s.
Thus, initial velocity (u) = 8 m/s.
Time taken (t) = 3 secs.
Final velocity (v) = 23 m/s.
Thus, Acceleration(a) = ( v - u) /t
=> a = ( 23 - 8)/3
=> a = 15/3 = 5.
Thus, Acceleration is 5 m/s^2.
➡️ Hence, the Acceleration is 5 m/s^2.
________
Hope this helps,.
If helps, please mark 'thanks'.
________
REGARDS, ARNAB ✌️
THANK YOU
Here is your answer,.⬇️⬇️
_________
The wind was blowing at 8 m/s.
In 3 seconds, it blows with a velocity 23 m/s.
Thus, initial velocity (u) = 8 m/s.
Time taken (t) = 3 secs.
Final velocity (v) = 23 m/s.
Thus, Acceleration(a) = ( v - u) /t
=> a = ( 23 - 8)/3
=> a = 15/3 = 5.
Thus, Acceleration is 5 m/s^2.
➡️ Hence, the Acceleration is 5 m/s^2.
________
Hope this helps,.
If helps, please mark 'thanks'.
________
REGARDS, ARNAB ✌️
THANK YOU
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