Physics, asked by anandkumarsingh6950, 11 months ago

In a superheterodyne receiver, the IF is 455 kHz.
If it is tuned 1200 kHz, the image frequency will be
(a) 1562 kHz (b) 1675 kHz
(c) 2110 kHz (d) 2025 kHz

Answers

Answered by NirmalPandya
2

Given:

  • In a superheterodyne receiver, IF=455kHz
  • It is tuned to 1200 kHz

To find:

  • Image frequency

Solution:

  • Any signal is capable of interfering with superheterodyne receiver if,
  • Image frequency = Tuned Signal ± 2×I.F
  • Tuned frequency = 1200 kHz and IF=455 kHz is given.
  • ∴ Image frequency = 1200 ± 910
  • Hence, Image frequency = 2110 kHz or 290 kHz.
  • On verifying with options we can find that 2110 kHz matches with our answer.

Answer:

  • The image frequency will be (c) 2110 kHz
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