Question

In a survey among 8 - School students, 68 % of those surveyed were in favors of atleast
one of the three magazines - A, B &C. 38 % of those surveyed favored magazine A, 26 %
favored magazine B & 36% favored magazine C. If 11% of those surveyed favored all three
magazine. What percent of those surveyed favored more than one of the three magazines?​

Answer 1

Answer:

During the survey it is found that 48% preferred coffee, 54% liked tea and 64% like to smoke.

Now, 28% liked coffee and tea

32% liked to smoke and have tea

30% liked to smoke and have coffee

6% liked none of these.

Now, we can use Venn diagram to solve this problem:

The total percentage should be 100%, so,

100\%=(48+54+64-28-32-30+x+6)\%100%=(48+54+64−28−32−30+x+6)%

Where 'x' is the percentage of people who liked all of them.

So,

100=82+x100=82+x

x=100-82=18x=100−82=18

x=18\%x=18%

So it is 18% of the total students who like all of them.

Now, we need to find the number of students who like coffee and smoking but not tea.

Refer the diagram:

People who like to smoke and have coffee is:

30\%-18\%=12\%30%−18%=12%

There are 2000 students who were surveyed so 12% of 2000 is:

12\%\times 2000=0.12\times2000=24012%×2000=0.12×2000=240

So, there are 240 students who like to have coffee and smoke but not tea.