Math, asked by shannu8465, 20 days ago

In a survey conducted among 2000 Junior Assistants in an office, it was found that 48% preferred coffee, 54% liked tea and 64% used to smoke. If 28% used coffee and tea, 32% used tea and smoke and 30% used coffee and smoke, then the percentage of clerks who use only coffee, given that 6% did none of these.

Answers

Answered by crazydaisy07
0

Step-by-step explanation:

During the survey it is found that 48% preferred coffee, 54% liked tea and 64% like to smoke.

Now, 28% liked coffee and tea

32% liked to smoke and have tea

30% liked to smoke and have coffee

6% liked none of these.

Now, we can use Venn diagram to solve this problem:

The total percentage should be 100%, So,

100% = (48 +54 30+x+6)%

+

64

28

32

Where 'x' is the percentage of people who liked all of them.

So,100 = 82 + x

x = 100 82 18 =

= 18% X=

So it is 18% of the total students who like all of them.

Now, we need to find the number of students who like coffee and smoking but not tea.

Refer the diagram:

People who like to smoke and have coffee is:

30% 18% = 12%

There are 2000 students who were surveyed so 12% of 2000 is:

12% × 2000 = 0.12 × 2000 = 240

So, there are 240 students who liketo have coffee and smoke but not tea.

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