In a survey of 200 children, it was found that 142 like outdoor games while 58 like indoor games. Find the probability that a child chosen at random (1) likes outdoor games (ii) likes indoor games.
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Answered by
5
Answer:
71/100-outdoors
29/100-indoors
explanation
total number of outcomes-200
p(outdoors)=142/200
=71/100
p(indoors)=(200-142)/200
=58/200=29/100
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1
The answer is below in the picture.
Explanation:
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