Question

in a survey of 200 children it was found that 142 like outdoor games while 58 likes indoor game . Find the prodlity that a child chosen at random like . a) indoor games b) outdoor games

Answer 1

a) probability of chosen indoor game p(i) 58/200 = 13/50

b) probability of chosen outdoor game p(o) 142/200 = 18/25

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Answer 2

Total number of children = 200

Number of children like indoor games = 58

$Probability\: (child \:like \:indoor \:games) = \frac{number\: of \:children \:like \:indoor\: games} {total \:number \:of\:children} \\ \\ Probability (child \:like \:indoor \:games) = \frac{58}{200} = \frac{29}{100} = 0.29$

Number of children like outdoor games = 142

$Probability (child \:like \:outdoor \:games) = \frac{number\: of \:children \:like \:outdoor\: games} {total \:number \:of \:children} \\ \\ Probability (child\: like \:outdoor\: games) = \frac{142}{200} = \frac{71}{100}$