Question

In a survey of 200 girls, it was found that 90 like tea while 110 dislike it. Out of these girls, one girl
chosen at random. What is the probability that the chosen girl
i) Likes tea
ii) Dislikes teaIn a survey of 200 girls, it was found that 90 like tea while 110 dislike it. Out of these girls, one girl
chosen at random. What is the probability that the chosen girl
i) Likes tea
ii) Dislikes tea

Answer 1

Answer:

Given

in a survey of 200 girls

110 disliked

Rest ,that is 90 liked

If a girl is chosen random

The probability of

i) She likes tea

We know

probability=number of outcome/total number of outcome

that is

p(likes the tea)=90/200

you can further simplify it as

9/20

therefore the probability of "likes the tea"=9/20

ii) She dislikes tea

We know

probability=number of outcome/total number of outcome

that is

p(dislikes the tea)=110/200

you can further simplify it as

11/20

therefore the probability of "dislikes the tea"=11/20

we know sum of all probabilities of an event=1

let's check whether it's correct or not

2 probabilities are here in this event

that is

$\frac{9}{20} + \frac{11}{20} = 1 \\ \\ \frac{9 + 11}{20} = 1 \\ \\ \frac{20}{20} = 1 \\ 1 = 1$

L.H.S=R.H.S

hence verified

hope it helps