Math, asked by AnishSehrawat7, 24 days ago

In a survey of 20000 family of a city it was found that 40% families read Newspaper (P) 20% families read news paper (Q), 10% Jamilies read newspaper (R), 4% buy (P) & (Q), 3% buy (Q) & (R) and 5% buy (P) & (R), If 2% family buy all three newspaper then find (1). number of family buying newspaper (P) only (Q) only, (R) only
(2). number of family buying exactly one there newspaper of the
(3). number of family buying exactly two of the three newpaper
(4). number of family buying at least one news paper
(5). number of family buying no news paper (6). number of family buying 2 news paper buying atmost​

Answers

Answered by wwwanshupriya1999
0

Answer:

Correct option is A)

n(A)=40%of10,000=4,000

n(B)=20%of10,000=2,000

n(C)=10%of10,000=1,000

n(A∩B)=5%of10,000=500

n(B∩C)=3%of10,000=300

n(C∩A)=4%of10,000=400,

n(A∩B∩C)=2%of10,000=200

We want to find n(A only)=n(A)–[n(A∩B)+n(A∩C)]+n(A∩B∩C)

n(A only)=4000–[500+400]+200=4000–700=3300

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