Question

In a survey of 40 students in a class, 10 were fond of having pineapple juice, 15 were found of orange juice and 7 liked to have both pineapple as well as orange juice. Find how many students were taking neither pineapple juice nor orange juice?
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Answer 1

Answer:

8

Step-by-step explanation:

Total no. of students =40

pineapple juice=10

Orange juice=15

Pineapple juice and orange juice=7

Sum of all students fond if juices =10+15+7=32students

No. of students neither like orange nor pineapple juice = 40students -32students = 8students

8 Students. Answer

Answer 2

Answer:

Number of students who were taking neither Pineapple nor orange were 22.

Step-by-step explanation:

Given,40 students in a class, 10 were fond of having pineapple juice, 15 were found of orange juice and 7 liked to have both pineapple as well as orange juice.

So, total number of students are 40.

Therefore,$n(S)=40$

Number of students who like Pineapple juice are 10.

So,$n(P)=10$

Number of students who like Orange juice are 15.

So,$n(O)=15$

Number of students who like both are 7.

So,$n(P ∩ O)=7$

We know,

$n(P∪O)=n(P)+n(O)−n(P∩O)$

=10+15−7

=25-7=18

Number of students who taking neither Pineapple nor orange juice were

$n( P∪O)=n(S)−n(P∪O)$

=40−18

=22